Question

Fig. 1.33 shows a uniform metre rule placed on a
fulcrum at its mid-point 0 and having a weight 40 gf
at the 10 cm mark and a weight of 20 gf at the 90 cm
mark. How can the rule be brought in equilibrium by using an additional weight of 40 gf?

step by step explanation please.

Chapter: Force.

Class-10 ICSE.

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Answer 1

Explanation:

Let us find individual moments of force.Considering 40 gf and 10 cm mark then 40 gf is at a distance of 40 cm from point O. we get moment of force is equal to 40∗40=1600gfcm.

Now let us consider 20 gf and 90 cm mark then 20 gf is at a distance of 40 cm to the right to O. We get moment of force as 20∗40=800gfcm. Both are not equal hence not in equilibrium.As 1600 gf cm is in anticlockwise in direction it turns in that anti clockwise direction.