Fig 1.35 shows two forces each of magnitude 10 N acting at the points A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of the two forces about the point (i) A, (ii) B and (iii) O, situated exactly at the middle of the two forces.
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Answers
Position A - At minimum distance
from fixed point
Position O- At some distance from
fixed point
Position B- At minimum distance
from fixed point
Moment of force =
force*perpendicular distance from fixed point
At position A : force = 10N
distance=0m
Moment of force =10 * 0
=0 Nm
At position B : force = 10N
distance=0m
Moment of force =10 * 0
=0 Nm
At position O : force = 10N
distance= 50/2
= 25m
Moment of force =10 * 25
=250 Nm
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