Question

Fig. 1.62
9
In the figure, in ABC. point D on
Side BC is such that.
angle BAC=angle ADC
Prove that, CA^2= CB XCD
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Answer 1

Answer:

Hi! hope this helps:) brainiest answer?

Step-by-step explanation:

Given in ΔABC, ∠ADC = ∠BAC

Consider

ΔBAC and ΔADC

∠ADC = ∠BAC (Given)

∠C = ∠C (Common angle)

∴ ΔBAC ~ ΔADC (AA similarity criterion)

AB/AD=CB/CA=CA/CD

Consider CB/CA=CA/CD

CA^2=CB×CD

Answer 2

Answer:

✌hey mate ✌

here is the answer

➡️in triangle ABC point d on side BC is such that angle bac is equal to angle adc prove that ca square is equal to the cd ×cb

hope it helps u deaR ❤

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