Question

Fig. 1.63
9. In the figure, in A ABC, point D on
side BC is such that,
Z BAC = ADC.
B
D
Prove that, CA = CB X CD​

Answer 1

Answer:

In △ADC and △BAC

∠ADC=∠BAC (Given)

∠C is Common

∴ by AA Criterion of Similarity, △ADC ∼ △BAC

⇒ AD/BD = Dc/AC = Ac/Bc

⇒ Dc/AC = AC/Bc

∴ CA^2=CB×CD