Fig 1 shows 6 equilateral triangle are arranged to form a regular hexagon of side a.
Fig 2 ,a regular hexagon of side 2a is formed with 24 equilateral triangles .If a regular hexagon of length 5a is formed by n equilateral triangles , find n/ 6.
the fig is attached above
please let me know the answer
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Step-by-step explanation:
The area of a regular hexagon of side 5a
=the area of 6 equilateral triangles of side 5a
=6√3/2×(5a)^2
The area of an equilateral triangle of side a
=√3/2×a^2
Therefore n=6{√3/2×(5a)^2}/{(√3/2×a^2)
=6×25a^2/a^2
Therefore n/6=25a^2/a^2=25
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