Question

Fig. 10.100, AB || CD and EF ||DQ. Determine Z PDO, ZAED and 2 DEF.​

Answer 1

Step-by-step explanation:

Given : AB∣∣CD;EF∣∣DQ

To find : ∠PDQ

∵AB∣∣CD and PE is transversal

∠PDC and ∠PEA are corresponding angles.

∴PEA=34

∘

∠PEA+∠PEF+∠FEB=180

∘

(Linear pair)

34

∘

+∠PEF+∠FEB=180

∘

∠PEF=180

∘

−34

∘

−78

∘

∠PEF=68

∘

∵EF∣∣DQ

∠PDQ=∠PEF=68

∘

∴∠PDQ=68

∘

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Answer 2

Answer:

ugh

Step-by-step explanation:

where is the figure man??????