Math, asked by nihal99606, 11 months ago

Fig. 10.17
In Fig. 10.18, PO is the diameter of the circle. ZSQP is equal to
(a) 40°
(6) 60°
(c) 50°explain the question

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Answered by challu

1

opposite angles in a quadrilateral =180

150+x=180

x=30

HOPE IT'S HELPFUL...

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