Question

Fig. 10.90
16. In Fig. 10.91, AP is a tangent to the circle with centre O such that OP = 4 cm and
ZOPA = 30°. Then, AP=
O
30°
A
P.​

Answer 1

Answer:

Step-by-step explanation:

Op=4cm

Angleopa=30

Cos30=base/hypotenuse

Root3/2=base/4

Base=2root3

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