Question

Fig. 11.22
9. ABCD is a kite. (Fig. 11.23)
(a) IS AD = AB?
(c) IsDAO=/BAO?
(e) Is AOB = Z AOD = 90°?
(b) Is ADO = 2 ABO?
(d) Is AOB = AOD?

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Answer 1

Answer:

a answer is always right now

Answer 2

Answer:

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Step-by-step explanation:

option a

□ABCD is a kite where AC and BD are diagonals intersect at point O.

∠OBC=20 and ∠OCD=40  

 

 

We know, in kite diagonals intersect at right angles.

∴  ∠AOD=∠DOC=∠BOC=∠AOB=90  

o

 

In △BOC,

⇒  ∠BOC+∠OBC+∠OCB=180  

⇒  90  +20

∠OCB=180

 ⇒  110          

∠OCB=180

∴  ∠OCB=70

⇒  AB=BC               [ Adjacent sides are equal in length ]

⇒  ∠ACB=∠BAC=70  

 [ Angles opposite to equal sides are equal ]  

In △AOB,

⇒  ∠ABO+∠AOB+∠OAB=180  

⇒  ∠ABO+90

70=180  

⇒  ∠ABO=20  

⇒  ∠ABC=∠ABO+∠OBC

 =20 +20   =40

∴  ∠ABC=40