Question

Fig 11.23
8. AABC is isosceles with AB AC = 7.5 cm and BC-9 cm (Fig 11.26). The height
AD from A to BC, is 6 cm. Find the area of AABC. What will be the height from C
to AB i.e., CE?​

Answer 1

Step-by-step explanation:

Area of triangle - 1/2 × Base × Corresponding Height

Area - 1/2 × BC × AD

1/2 × 9cm × 6cm

27cm^2

If we calculate area from base AB

Area - 27cm^2

1/2 × AB × CE - 27cm ^2

1/2 × 7.5cm × CE - 27cm^2

CE - 27×2×1/7.5

CE - 54/7.5

CE - 540/75

CE - 7.2cm

Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM