Question

Fig 11.25
8. ABC is isosceles with AB=AC = 7.5 cm and BC =9 cm (Fig 11.26). The height
AD from A to BC, is 6 cm. Find the area of ABC. What will be the height from C
to AB i.e., CE?​

Answer 1

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Answer 2

Answer:

In ΔABC, AD=6cm and BC=9cm

Area of triangle=21×base×height=21×BC×AD

=21×9×6=27 cm2

Again, Area of triangle=21×base×height=21×AB×CE

⇒27=21×7.5×CE

⇒ CE=7.527×2

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm.