Question

Fig. 12.16
A floral design on a floor is made up of 16 tiles
which are triangular, the sides of the triangle
being 9 cm, 28 cm and 35 cm (see Fig. 12.18).
Find the cost of polishing the tiles at the rate
of 50p per cm?
parallel
answer it correctly and fast​

Answer 1

Answer:

₹28800$\sqrt{x} 6$

Step-by-step explanation:

S = (9 +28 + 35)/2

= 72/2 =36

AREA = $\sqrt{x} S(S-9)(S-28)(S-36)$ = $\sqrt{x} 36*27*8*1$ =36$\sqrt{x} 6$ cm

          = 576$\sqrt{x} 6$

cost = 576$\sqrt{x} 6$ x 50 = ₹ 28800$\sqrt{x} 6$

Answer 2

Area of tiles = 16 x area of 1 Δ

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)36×27×8×1

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)36×27×8×1366cm2

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)36×27×8×1366cm2Area of tiles = 16 ×366

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)36×27×8×1366cm2Area of tiles = 16 ×366=1410.20.

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)36×27×8×1366cm2Area of tiles = 16 ×366=1410.20.Cost of polishing per cm2 = 50.

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)36×27×8×1366cm2Area of tiles = 16 ×366=1410.20.Cost of polishing per cm2 = 50.Cost of polishing = 1410.90 cm2

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)36×27×8×1366cm2Area of tiles = 16 ×366=1410.20.Cost of polishing per cm2 = 50.Cost of polishing = 1410.90 cm21410.90 x 21

Area of tiles = 16 x area of 1 ΔS=2a+b+c=29+28+35=272=36Area=36(36−9)(36−28)(36−35)36×27×8×1366cm2Area of tiles = 16 ×366=1410.20.Cost of polishing per cm2 = 50.Cost of polishing = 1410.90 cm21410.90 x 21705.45