Question

Fig. 12.26 depicts a racing track whose left and right ends are semicircular.
Fig. 12.26
The distance between the two inner parallel line
segments is 60 m and they are each 106 m long. If
the track is 10 m wide, find :
the distance around the track along its inner edge
(i) the area of the track.
​

Answer 1

Answer:

The distance around the track along its inner edge

=EF+HG + circumference of semicircle with diameter EH+circumference of semicircle with diameter FG

circumference of semicircle with diameter EH + Circumference of semicircle with diameter FG

=2×π×30=60πm

∴ The distance around the track along its inner edge

=60π+106+106

=

7

2804

m

∴ Area of track = Area of rectangle ABFE + Area of rectangle HGCD + (Area of semicircle with diameter AD − Area of semicircle with diameter EH) + (Area of semicircle with diameter BC − Area of semicircle with diameter FG)

=(106×10)+(106×10)+(

2

π

×40×40−

2

π

×30×30)+(

2

π

×40×40−

2

π

×30×30)

=2120+2200=4320m

2

Step-by-step explanation:

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