Question

Fig. 15.
12. In Fig. 15.30, A ABC is an isosceles triangle with AB = AC = 7.5 cm and
BC = 9 cm. The height AD from A to BC is 6 cm. Find the area of A ABC. What
will be the height from C to AB, i.e., CE ?
7.5 cm
B​

Answer 1

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Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM