Fig. 15.
12. In Fig. 15.30, A ABC is an isosceles triangle with AB = AC = 7.5 cm and
BC = 9 cm. The height AD from A to BC is 6 cm. Find the area of A ABC. What
will be the height from C to AB, i.e., CE ?
7.5 cm
B
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Step-by-step explanation:
Area of ∆ ABC = 1/2 × Base × Height
= 1/2 × BC × AD
= 1/2 × 9 × 6
= 27 cm²
Area of ∆ ABC = 1/2 × Base × Height
= 1/2 × AB × CE
27 cm² = 1/ 2 × 7. 5 × CE
CE = 7.2 CM
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