Question

Fig 3.35 shows a brick of weight 2 kgf and dimensions 20 cm x 10 cm x 5 cm placed in three different positions on the ground. Find the pressure exerted by the brick in each case.​

Answer 1

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Answer 2

Explanation:

given,

force=2kgf

we know that

$presure = \frac{force}{area}$

CASE 1

area=L×B=20×10=200cm²

presure=F/A=2/200=1/100=00.1

p=00.1kgf/cm²

CASE 2

area =L×B=10×5=50cm²

presure=F/A=2/50=1/25=0.04

presure in case 2=0.04kgf/cm²

CASE 3

area=L×B=20×5=100cm²

presure=F/A=2/100=1/50=0.02

presure=0.02kgf/cm²