Question

Fig. 3.38
In fig 3.39 chord AB chord CD,
A
Prove that,
arc AC = arc BD
C
B
Fig. 3.39​

Answer 1

Answer:

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Answer 2

Answer:

arc AC is congruent to arc BD

Step-by-step explanation:

let a circle with radius r and center O.

in which two chords at equal distance from O are AB and CD.

to prove :- arc AC =ac BD

proof:- in ΔAOB and ΔCOD

AB =CD (given)

OC=OA (radius of circle)

OB=OD (radius of circle)

so ΔAOB ≅ ΔCOD (SSS)

as we know length of arc = radius * angle subtended by arc at center

so arc AC = r* α

and arc BD = r*α

so it is clear that

arc AC =ac BD

Hence proved

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