Question

Fig
3. If tangents PA and PB from a point P to a circle with centre o are inclined to each other
at angle of 80°, then Z POA is equal to
(B) 60°
(D) 80°
(A) 50°
(C) 70°​

Answer 1

Answer:

PA and PB are inclined with centre O at an angle of 80°.

Therefore, each one is of 40°.

That means angle P is 40° half of PA and PB which is 80°.

Angle A is 90°. Reason is tangent theorem.

And angle O we have to find out.

So, angle O + angle A + angle P = 180°

i.e. O + 90° + 40° = 180°

i.e. O+ 130° = 180°

i.e. O = 180° - 130°

i.e. O = 50°

Answer :- 50°