Chemistry, asked by palgeeta404, 1 month ago

FIG. 4.14
Boron
At. No. 5 Mass No. 11
Carbon
At. No. 6 Mass No. 12
Nitrogen
AL No. 7 Mass No. 14
Oxygen
At No. 8 Mass No. 16
p=5
p=7
2/3
6 בה ח
p = 6
n = 6
2/4
2/5
p=8
n = 8
n = 7
216
Fluorine
Neon
Sodium
Magnesium
At. No. 9 Mass No. 19 At. No. 10 Mass No. 20 At. No. 11 Mass No. 23 At. No. 12 Mass No. 24
p=9
P = 10
p = 11
277 n = 10
2/8 n = 10
2/8/1 n = 12
P = 12
2/8/2 n = 12​

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