Question

Fig. 6.1 shows a circuit in which a voltmeter is placed across a resistor.​

Answer 1

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1. Bez the voltage is more than its maximum value which is 3.0V so it unsuitable
2. Bez the voltage is very less according to its highest value and for 30V voltmeter there will be very minute deflection which can't be measured properly so it is unsuitable
3. Formula is V=IR

$\frac{12}{4} =I$

$3 A=I (Current)$

5. Total resistance =R1+R2= 30

Current =3 A ( same in whole circuit)

So Voltage = IR

V = 30× 3= 90 V ans......

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