Physics, asked by 99ec25, 3 months ago

Fig 6.21 shows a manometer used to measure the pressure difference between the air inside a plastic container and the atmosphere outside a pressure difference of 100 Pa causes a one centimeter difference in water lvl a) Using Fig 6.21 determine the pressure difference in Pa shown by manometer

Answers

Answered by pushkarsharma2006
1

Explanation:

(a) For figure (a)

Atmospheric pressure, P

0

= 76 cm of Hg

Difference between the levels of mercury in the two limbs gives gauge pressure

Hence, gauge pressure is 20 cm of Hg.

Absolute pressure = Atmospheric pressure + Gauge pressure

=76+20=96cm of Hg

For figure (b)

Difference between the levels of mercury in the two limbs =–18cm

Hence, gauge pressure is –18 cm of Hg.

Absolute pressure = Atmospheric pressure + Gauge pressure

=76cm–18cm=58cm

(b) 13.6 cm of water is poured into the right limb of figure (b).

Relative density of mercury = 13.6

Hence, a column of 13.6 cm of water is equivalent to 1 cm of mercury.

Let h be the difference between the levels of mercury in the two limbs.

The pressure in the right limb is given as:

PR= Atmospheric pressure + 1 cm of Hg

=76+1=77cm of Hg ….. (i)

The mercury column will rise in the left limb.

Hence, pressure in the left limb, PL=58+h ..... (ii)

Equating equations (i) and (ii), we get:

77=58+h

∴h=19cm

Hence, the difference between the levels of mercury in the two limbs will be 19 cm.

Answered by AreebShahzad
0

Answer:60000 Pa

Explanation: the difference between the water level is 60 cm and if 100 Pa = 1 centimeter then 60 centimeter is equal to 60,000 pa

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