Question

Fig. 7.1 shows an equilateral triangle with th
lengths of its sides given in terms of a and
49 cm
3b cm
(a + b + c)cm​

Answer 1

Answer:

The sides of equilateral triangle is (2a-b),(a+3b) and (2a-2b+1)

Then (2a-b)=(1+3b) = (2a-2b+1)

If 2a-b=2a-2b+1

Then -b+2b=1 or b=1

If 2a-b=a+3b (put the value of b=1

Then 2a-a=1+3 or a=4

Then perimeter of equilateral triangle=2a-b+a+3b+2a-2b+1=8-1+4+3+8-2+1=21 cm

Step-by-step explanation:

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Answer 2

Answer:

The sides of equilateral triangle is (2a-b),(a+3b) and (2a-2b+1)

Then (2a-b)=(1+3b) = (2a-2b+1)

If 2a-b=2a-2b+1

Then -b+2b=1 or b=1

If 2a-b=a+3b (put the value of b=1

Then 2a-a=1+3 or a=4

Then perimeter of equilateral triangle=2a-b+a+3b+2a-2b+1=8-1+4+3+8-2+1=21 cm