Question

Fig. 7.19 port 5. Line) is the bisector of an angle _ A and B is any on I. BP and BQ are perpendiculars from B to the arms of Z A (see Fig. 7.20). Show that: (1) A APB=AAQB (1) BP = BQ or B is equidistant from the arms of LA IB CA P Fig. 7.20​

Answer 1

Where are the figures?????

Post them also..

Answer 2

Answer:

LA IB CAP fig.7.20 A APB=AAQB