Question

Fig.
7.
In 4 ABC, bisectors of angleA and B intersect at point 0. If angleC = 70°. Find measure​

Answer 1

Answer:

In a triangle, the sum of interior angle =180

∘

Thus, in △ABC ,

∠A+∠B+∠C=180

∘

∠C=70

∘

,

Hence,

∠A+∠B=130

∘

Bisector of ∠A and∠B intersect at point O then

2

∠A

+

2

∠B

=65

∘

∠OAB+∠OBA=65

∘

Now, in △OAB,

∠OAB+∠OBA+∠AOB=180

∘

⇒∠AOB=115

∘

Step-by-step explanation:

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