Question

Fig. 76
11. In Fig. 77, DE || QR, AP and BP are bisectors of ZEAB and ZRBA respectively. Find
ZAPB.​

Answer 1

Answer:

Step-by-step explanation:

Let angle EAP = angle BAP = x    (AP bisector)

Let angle RBP = angle PBA = y    BP is bisector

angle EAB + angle ABR = 180 degrees  as AE and BR are parallel

2 * x + 2 * y = 180 deg        x + y = 90

angle APB = 180 - x - y  in trianle APB

angle APB = 180 - 90 = 90 deg\

pls mark as brainliest