Question

Fig. 9.11
SSS
3. In Fig. 9.12, PS = RS and PQ = RQ
(0) Is APQS = ARQS?
(ii) State the three pairs of matching parts you have used to
answer (i).
(ii) ZP=7B
Fig. 9.12
A​

Answer 1

Answer:

ANSWER

Given:AB=PQ=BQ

In△ABC&△PQR

⟹AB=PQ

∠ABC=∠PQR=90  

∘

 

BC=RQ

∴△ABC≅△PQR

⟹AC=PR(C.P.C.T)

In△ABR

AB  

2

+BR  

2

=AR  

2

 

⟹AB  

2

+(BC+CR)  

2

=AR  

2

−(1)

In△PCR:

⟹PQ  

2

+QC  

2

=PC  

2

 

⟹PQ  

2

+(QR+CR)  

2

=PC  

2

 

In(1)&(2),

∵AB=PQ(given)

andBC=QR(given)

⟹AR  

2

=PC  

2

(from(1)&(2))

AR=PC−(3)

In△ABR&△PQC

⟹AB=PQ

∠ABR=∠PQC=90  

∘

 

AR=PC−(from(3))

∴△ABR≅△PQCbyR.H.S

Step-by-step explanation:

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