Question

Fig. 9.32
5. In Fig. 9.33, ABC and BDE are two equilateral
triangles such that D is the mid-point of BC. If AE
intersects BC at F, show that
A
(i) ar (BDE)
1
ar (ABC)
4
1
(i) ar (BDE)=
2
ar (BAE)
FD
B
(iii) ar (ABC)= 2 ar (BEC)
(iv) ar (BFE) = ar (AFD)
(v) ar (BFE) = 2 ar (FED)
Fig. 9.33
(vi) ar (FED)
1
ar (AFC)
8
[Hint: Join EC and AD. Show that BE || AC and DE || AB, etc.)​

Answer 1

Answer:

if ex eff tb hhbbbb um ppb ssh if Dhabi

Answer 2

Answer:

Fig.9.32

Step-by-step explanation:

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