Physics, asked by thakurhemant846, 4 months ago

fig A
27. Below Figure shows a rectangular loop conducting PQRS in which the arm PQ is free to
move. A uniform magnetic field acts in the direction perpendicular to the plane of the
loop. Arm PQ is moved with a velocity v towards the arm RS. Assuming that the arms
QR, RS and SP have negligible resistances and the moving arm PQ has the resistance r,
obtain the expression for (1) Current in the loop (ii) force and (iii) Power required to
move arm PQ.
fig A
OR
Derive expression for self inductance of a long air-cored solenoid of length I, cross
sectional area A and having number of turns N.​

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Answers

Answered by dangergamer284
1

Answer:

cn cn cbfbdbfbfnfnznxbxnbxbxbzxbxbbccbxhdjdididijffjfjfhrjrjrfjfjfjfjvjvjricifjfcbfbdbfbfnfnznxbxnbxbxbzxbxbbccbxhdjdididijffjfjfhrjrjrfjfjfjfjvjvjricifjfdjdjdjdjrjrjrfhfcbfvnvnvnvncnncnbnh gn gn nngngnggngbg ng ng nggjgjggghhxdjdjdjdjrjrjr me nrnrnrnrnrrnrnrnf

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