Question

fig.
ABC=69º
ACB= 31° find
BDC.
u) In fig. P is a point in the Interior of a parallelogram ABCD show that
(i) ar (APB) + ar (PCD) ar (ABCD)
(ii) ar (APD) + ar (PBC) = ar (APB) + ar (PCD)​

Answer 1

Answer:

Angle BDC is80 degree

Step-by-step explanation:

Apply angle sum property of triangle