fig.
ABC=69º
ACB= 31° find
BDC.
u) In fig. P is a point in the Interior of a parallelogram ABCD show that
(i) ar (APB) + ar (PCD) ar (ABCD)
(ii) ar (APD) + ar (PBC) = ar (APB) + ar (PCD)
Answers
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Answer:
Angle BDC is80 degree
Step-by-step explanation:
Apply angle sum property of triangle
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