Question

fig , B Dadce
point
th
intersect cach
PBC PO
why​

Answer 1

Given :  In figure, BD and CE intersect each other at the point P.

To Find : Is ΔPBC ~ ΔPDE  

Solution:

PB = 5cm

PC = 6 cm

PD = 10 cm

PE = 12 cm

PB/PD  = 5/10  = 1/2

PC/PE = 6/12 = 1/2

=> PB/PD = PC/PE = 1/2

∠BPC = ∠DPE   ( Vertically opposite angles)

Δ PBC and ΔPDE  

PB/PD = PC/PE

∠BPC = ∠DPE

=> Δ PBC ≈  ΔPDE   ( Using SAS)  

Yes ΔPBC ~ ΔPDE  based on SAS similarity criteria

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