Fig shows the v-tgraph for the motion of a lift. The total distance travelled by the lift is. (а) 55 m (b) 50 m (c) 45 m (d) 40 m .
Answers
_________________
If the last second is given as 10 second!
Explanation: In a velocity time graph if we have to find out the distance travelled then we have to find out the area of the given figure.
Required solution:
~ Firstly let us find out the area of triangle first by using suitable formula!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of triangle
→ Distance = ½ × B × H
→ Distance = ½ × (4-0) × (10-0)
→ Distance = ½ × 4 × 10
→ Distance = ½ × 40
→ Distance = 1 × 20
→ Distance = 20 m
~ Now let us find out the area of given rectangle by using suitable formula!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of rectangle
→ Distance = L × B
→ Distance = (6-4) × (10-0)
→ Distance = 2 × 10
→ Distance′ = 20 m
~ Now let us find out the area of triangle second by using suitable formula!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of triangle
→ Distance = ½ × B × H
→ Distance = ½ × (10-6) × (10-0)
→ Distance = ½ × 4 × 10
→ Distance = ½ × 40
→ Distance = 1 × 20
→ Distance″ = 20 m
~ Now let us find out the total distance by using suitable formula!
→ Total distance = Distance + Distance′ + Distance″
→ Total distance = 20 + 20 + 20
→ Total distance = 40 + 20
→ Total distance = 60 m
- Dear user I don't know that what is the last second given in the graph. But may be it is 10 seconds or 9 seconds. So if it is 10 seconds then answer will be 60 metres but if it is 9 seconds then answer must be 55 metres according to the option.
_________________
If the last second is given as 9 second!
~ Firstly let us find out the area of triangle first by using suitable formula!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of triangle
→ Distance = ½ × B × H
→ Distance = ½ × (4-0) × (10-0)
→ Distance = ½ × 4 × 10
→ Distance = ½ × 40
→ Distance = 1 × 20
→ Distance = 20 m
~ Now let us find out the area of given rectangle by using suitable formula!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of rectangle
→ Distance = L × B
→ Distance = (6-4) × (10-0)
→ Distance = 2 × 10
→ Distance′ = 20 m
~ Now let us find out the area of triangle second by using suitable formula!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of triangle
→ Distance = ½ × B × H
→ Distance = ½ × (9-6) × (10-0)
→ Distance = ½ × 3 × 10
→ Distance = ½ × 30
→ Distance = 1 × 15
→ Distance″ = 15 m
~ Now let us find out the total distance by using suitable formula!
→ Total distance = Distance + Distance′ + Distance″
→ Total distance = 20 + 20 + 15
→ Total distance = 40 + 15
→ Total distance = 55 m
