Question

. Fig. shows the vertical section of frictionless surface. A block
of mass 2 kg is released from the position A its Kinetic Energy
as it reaches the position C is
(take acceleration due to gravity as 10 m/s?)
​

Answer 1

Answer:

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We know that,

• Block was at the height of 14m at A
• And at the height of 7m at C
• mass of the body = 2kg

Vertical height (h) = 14m - 7m

= 7m

According the law of conservation of energy,

• The potential energy of a body at height h is converted into kinetic energy when it falls down.

• So, the magnitude of kinetic energy of block just before hitting the ground is equal to the potential energy at height h which is mgh.

Therefore,

➝ Kinetic energy at C = mgh

➝ 2kg × 10m/s × 7m

➝ 140 J

Hence the required answer is 140 Joules