Figure 10(a) shows two charges q1 and q2 held a fixed distance d apart. (a) Find the strength of the electric force that acts on q1. Assume that q1 =q2 =21.3×10^-6C and d =1.52m. (b) A third charge q3=21.3×10^-6C is brought in and placed as shown in figure 10(b). Find the strength of the electric force that acts on q1 now.
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you can do this only by your help
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Coulomb's Law describes the force between two charged point-like particles: q1 * q2 F = k * ---------- r^2 where k = Coulomb's constant = 8.99 x 10^9 (N*m^2/C^2) q1 = charge on first particle (Coulombs) q2 = charge on second particle (Coulombs) r = distance between particles (meters)
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