Question

Figure 15.18 shows a sector of a circle of radius r cm containing an angle θ°. The area of the sector is A cm² and perimeter of the sector is 50cm.
(i)θ=360/π(25/r-1)(ii)A=25r-r²

Answer 1

Step-by-step explanation:

Hence Proved

Step-by-step explanation:

A sector of a circle of radius r cm

Angle of sector is

Formula: l=r@

Perimeter of sector is 50 cm

l+r+r=50

r@+2r=50

@=(50-2r) /r

@=2(25-2r) /r

Change into degree

(a)@=180/π×2(25/r-1)

@=360/π(25/r-1)

Hence Proved

(b)

Area of sector  =@/360×πr²

Area of sector =360/(360×π) ×(25/7r1) πr²

Area of sector, A=25r-r²

Hence Proved

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