figure 2.8 sides of angle pqr and angle xyz are parallel to each other prove that angle pqr is congruent to angle xyz
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Here,
PQ∥XY and PQ=XY
PR∥XZ and PR=XZ
Taking ΔPQR and ΔXYZ,
PQ=XY
PR=XZ
∠QPX=∠YXM=a
∠RPX=∠ZXM=b
∠XYZ=∠YXM+∠ZXM=a+b
∠XYZ=∠QPR=a+b
⇒ΔPQR≅ΔXYZ
Hence, proved.
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