Question

figure 21.10 show a circle with Centre O and radius 3 cm​

Answer 1

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let the radius be marked as R
so,
AD is the diameter or we can say diameter = 2*radius

1. it means that OA = R
2. BC = 2R
3.OA = BO = OC = OD (radius)


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(i guess it's not the full question)

Answer 2

1. OA = 3cm ( radius )
2. BC = 2r = d = 6cm
3.OA = OC =OD=OB ( all are radius )
4. By pgt ,
in tri.BOD :
BD^2 = OB^2 +DO^2

BD^2 = 9 + 9

BD^2 = 18

$3 \sqrt{2}$
So, 5 lines segments having length less than 6 cm are :

OA ( 3CM )

OB ( 3CM )

OD ( 3CM )

OC ( 3CM)

BD($3 \sqrt{2}$cm)

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