Question

Figure-4
18. The LCM of two numbers is 182 and their HCF is 13. If one of the numbers is 26, find the other,
19. Form a quadratic polynomial, the sum and product of whose zeroes are (-3) and 2 respectively.


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Answer 1

1. LCM × HCF = A × B

182 × 13 = 26 × B

B = 2,366/26

B = 91

hence another number is 91.

2. sum of zeroes :- -3

product of zeroes :- 2

a quadratic polynomial is in the form of

k{x² - (α + β)x + (αβ)}

k{x² - ( -3 )x + (2)

k(x² + 3x + 2)

hence the quadratic polynomial is x² + 3x + 2