Question

figure, AB = AC and MB = MC. Prove that angle ABM = _ACM.
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Answer 1

Given- AB=AC and MB=MC

To prove- ABM=ACM

Proof- AB=AC ( Given )

MB=MC ( Given )

B=B (Common)

By SSS

Triangle BAC= Triangle BMC

By CPCT

ABM=ACM

Answer 2

$\huge{\boxed {\mathfrak \pink {\fcolorbox {red}{blue}{AnSwEr}}}}$

Given- AB=AC and MB=MC

To prove- ABM=ACM

Proof- AB=AC ( Given )

MB=MC ( Given )

B=B (Common)

By SSS

Triangle BAC= Triangle BMC

By CPCT

ABM=ACM