Question

Figure along side shows a body of mass m moving
with a uniform speed v along a circle of radius r.
The change in velocity in going from A to B is
(a) v √2 (b) v / √2
(c) v (d) zero

Answer 1

Answer:

Velocity at A=VA=Vj^

Velocity at B=VB=V(−i^)

=−Vi^

Change in velocity =VR−VA

=−Vi^−Vj^

Magnitude=(−V)2+(−V)2

=2V.

Answer 2

Answer:

Option A

Explanation:

Velocity at Point A = v(i cap)

Velocity at point B = v (j cap)

Therefore,

change in velocity = vi-vj

$= \sqrt{ {v}^{2} + {v}^{2} } \\ = \sqrt{2v }$