Question

figure, BE and CF are two
un the given figure
sual altitudes of AABC
w that (i) triangleABE=triangleACF,
(ii) AB = AC.​

Answer 1

Proof :- _____

In ∆ABE and ∆ACF

BE = CF ( Given )

< BAE = < CAF ( general sides )

<AEB = < AFC ( Each 90° ).°. ∆ABE =~ ∆ ACF ( by AAS congruence rule )ii ) ∆ABE =~ ∆ACF [ from (I) ,

already proved ).°.

AB = AC ( CPCT ).°. ABC is an isoscele triangle