Figure below shows a wheel which has a fixed axle passing through O. The wheel is kept stationary under the action of two forces horizontal force F1 at and a vertical force F2 at N.
(a) Copy the diagram and show the direction of F2.
(b) Which force is greater F1 or F2?
(c) Find the ratio between the forces. [ given MO = 2.5 cm, NO’ = 1.5 cm and
OO’ = 2 cm].
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Here is the Answer:
Explanation:
Direction of F2 is Anticlockwise
Since the distance between NO’ is smaller than MO Hence F2 is greater
Since F1*MO=F2*NO
=> F1/F2=NO/MO
=>F1:F2=1.5:2.5
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