Figure below shows two paths that may be
taken by a gas to go from a state A to a state
C. In process AB, 400 J of heat is added to
the system and in process BC, 100 J of heat
is added to the system. The heat absorbed
by the system in the process AC will be
(a) 460 J (b) 300 J (c) 380 J (d) 500 J
(2015 Cancelled)
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Answer:
460J
Explanation:
Net work done= Are of triangle= 1/2*4*10^4*2*10^-3 =
40 Joule
from 1st law Qnet= Wnet
so 400+100+x = 40 => 40-500=> x = -460 i.e. Heat is released
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