Question

figure D is the midpoint of side BC copper Triangle ABC and Angle A BD S 50 degree if ad is equal to BD is equal to CD then find the measure of of angle ACD​

Answer 1

Answer:

     ACD=40

Step-by-step explanation:

1 Step

BAD=50                    

BAD+ABD+ADB=180

50+50+ADB=180

100+ADB=180

ADB=80

2 step

ADC=180-80

ADC=100

3 Step

100+ACD+CAD=180

100+X+X=180

100+2x=180

2x=80

x=40