Figure given below shows the graph of velocity v of
particle moving along x-axis as a function of time t.
Average acceleration during t= 1 s to t= 7 s is
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Answer:
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v = final velocity
u = initial velocity
s = Distance
a = Acceleration
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✨ First case,
v = 0 m/s
u = 10 m/s
s = 20 m.
➡️ v^2 = u^2 + 2as
Or, 0 = 100 + 40a
Or, a = - 100 /40 = - 5/2.
.°. a = - 5/2 m/s^2
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✨Second case,
v = 0 m/s
u = 20 m/s
a = - 5/2 m/s^2
➡️ v^2 = u^2 + 2as
Or, 0 = 400 - 5s
Or, s = 400/5 = 80.
.°. The stopping distance will be 80 m.
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Thanks..
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