Question

figure gives the acceleration of 2.0 kg body as it moves from rest along x-axis while a variable force act on it from x = 0 metre to x = 9 metre. the work done by the force on the body when it reaches
1) x = 4 metre and
2) x = 27 As given in the figure... ​

Answer 1

Answer:

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Explanation:

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Answer 2

The work done is 42 J and 30 J.

Explanation:

Given that,

Mass of object = 2.0 kg

(I). x = 4 m

We need to calculate the work done by the force on the body

Using formula of under the curve

$W=m( \text{area of triangle+area of square})$

Put the value into the formula

$W=2\times(\dfrac{1}{2}\times1\times6+3\times6)$

$W=42\ J$

(II). x= 7 m

We need to calculate the work done by the force on the body

Using formula of under the curve

$W=m( \text{area of triangle+area of square})$

Put the value into the formula

$W=42+2\times(\dfrac{1}{2}\times1\times6-\dfrac{1}{2}\times1\times6-1\times6)$

$W=42-12\ J$

$W=30\ J$

Hence, The work done is 42 J and 30 J.

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Topic : work done

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