Question

Figure here gives the velocity-time graph for a boy
The distance travelled between t=1.0 second and
t = 7.0 second is nearest to:

(A) 1.5 m
(B) 3 m
(C) 12 m
(D) 15 m​

Answer 1

Answer:

distance traveled =area under v-t graph

distance= area of trapezium +area of triangle

distance =(1/2(4+1)×4)+(1/2×3×4)

d= 10+6

=16m

so it is nearest to 15m