Question

Figure is given please solve

Answer 1

Check the attachment and tell me if there's any problem

Answer 2

1).- In triangle ABD and Triangle ACD

AB = AC ( Given)

AD = AD ( Given)

Angle BDA = Angle ADC

Triangle ABD congruent to Triangle ACD
(RHS rule)

So BD = CD ( By cpct) ..............(1)



2).- In triangle FBE And triangle DBF

BE = BE (common)

Angle FBE = Angle DBE ( given) (BE is bisector)

Angle BFE = Angle BDE ( given) ( both are perpendicular)

Triangle FBE = Triangle DBE (AAS rule)

So ED = EF (By cpct) ............(2)