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2x+50=x+4y. (vertically opposite angles)
X=4y-50. ———1
2x+50=5y+10.
2x=5y-40————2
On substituting eq. 1 in 2
2(4y-50)=5y-40
8y-100+40-5y=0
3y-60=0
Y=60/3
Y=20
X=4y-50
=> x=30
Therefore,x=30 and y=20
If u want to find angles substitute value of x and y in the given equation
So angles are
X+4y=110
5y+10=110
X+4y=110
Hope this is what u need
X=4y-50. ———1
2x+50=5y+10.
2x=5y-40————2
On substituting eq. 1 in 2
2(4y-50)=5y-40
8y-100+40-5y=0
3y-60=0
Y=60/3
Y=20
X=4y-50
=> x=30
Therefore,x=30 and y=20
If u want to find angles substitute value of x and y in the given equation
So angles are
X+4y=110
5y+10=110
X+4y=110
Hope this is what u need
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