Question

figure show a2ohm resistor and 6ohm resistor connected in series with 4v battery. calculate the amount of charge passing through the battery in 10sec
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Answer 1

Answer:

Q = 5C

Explanation:

Equivalent resistance = 2ohm +6ohm

= 8ohm

V=4

therefore, we know that R =V/I

So that I=V/R,

ie, I=4/8=1/2.

Then, I=Q/t

or,Q=I×t

ie,Q=1/2×10

=5

Answer 2

Given,

1. A 2-ohm resistor and a 6-ohm resistor are connected in a series.
2. The resistors were connected to a 4 V battery.
3. Time(t) = 10 seconds

To find,

The amount of charge passing through the battery in the given time

Solution,

We will first find the equivalent resistance by adding both the resistances given,

Equivalent Resistance(R) = 2 ohm + 6 ohm = 8 ohm

Now, we know the formula of resistance,

Resistance(R) = $\frac{V}{I}$

⇒ Current (I) = $\frac{V}{R}$ = $\frac{4}{8}$ = $\frac{1}{2}$

We know that I = $\frac{Q(charge flowing in a given time)}{time}$

⇒ Q = I × t =  $\frac{1}{2}$ × 10 = 5 C

Hence, the amount of charge passing through the battery in 10 seconds is 5 C.