figure shows a battery of 12v and internal resistance 0.6 ohm connected to three resistor a b and c find the current in each resistor
Answers
Explanation:
Question = A battery
of 12 V and internal resistance 0.6 ohm connected to three resistors P,Qand R. Find the current in each resistor emf = 12 V. r=0.6ohm
Answer = the effective resistance of circuit is
R = 0.6 + 1 + 4.6/(4+6)
R = 4 ohm
so, current in the circuit is = 12/4 = 3 A
current in r and P is 3 A.
voltage drop on battery = 3 * 0.6 = 1.8V
voltage drop on P = 3 * 1 = 3 V
so, voltage drop on Q = voltage drop on R
=> Iq * 4 = Ir * 6 = 12 - 1.8 - 3
=> Iq = 7.2/4 = 1.8 A
and => Ir = 7.2/6 = 1.2
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Answer:
The equivalent resistance of B and C is given by 11 4 1 6 64 64R=+=+ ΩΩ ΩΩ ΩΩ()()==10 24 5 12ΩΩ or R==12 524ΩΩ. Total resistance in circuit = 1.0 W + 2.4 W + 0.6 W = 4.0 W
Currentthecircuit,VAinI==12 43Ω The potential difference across both B and C = 3.0 A × 2.4W = 7.2 V CurrentthroughVABI,. ..1 72 4018==Ω Currentthrough7.2V 6ACI,.212==Ω Thus, current through resistor A = 3.0 A Current through resistor B = 1.8 A Current through resistor C = 1.2 A