Question

Figure shows a horizontal solenoid connected to a battery and a switch. A copper ring is placed on a frictionless track, the axis of the ring being along the axis of the solenoid. As the switch is closed, the ring will
(a) remain stationary
(b) move towards the solenoid
(c) move away from the solenoid
(d) move towards the solenoid or away from it depending on which terminal (positive or negative) of the battery is connected to the left end of the solenoid.
Figure

Answer 1

It Moves Away from Solenoid

Explanation:

For the circuit,  

• The Current (A) will increment in the solenoid, streaming in clockwise course in the circuit.  

We Know, $E = - L\frac{di}{dt}$

• Because of this expanded current, the motion connected with the copper ring with increment with time, causing inducement in current.  

• This current will now contradict the reason delivering it.  

• Thus, the current in the copper ring will be moving anticlockwise.

• Presently, on the grounds that the headings of flows in the solenoid and ring are inverse, the ring will be repulsed and henceforth will move away from the solenoid.
• * Refer the figure attached